3. How Did The Period Of Rotation Vary As You Changed The Radius?

ballahboy

These questions are from a lab we only did.
1. Why is an unbalanced forcefulness required to produce circular motion?

2. The ratio of squared velocity to radius is a constant. In other words, the centripetal acceleration did not alter every bit the radius changed. Explain.

iii. In an entertainment park ride called the spinout, riders are positioned against the inside wall of a rotating drum. The drum begins to rotate and after a sure rotational speed is reached, the floor is lowered and the riders remain in position and do non fall. The diameter of the chamber is iv.3 meters and the period of rotation is ane.seven seconds. What is the centripetal dispatch of the rider? Approximately how many yard's does the rider experience?
For this ane, i got centripetal dispatch to equal 29.4m/s^2. Not sure if its right but i don't know how to find the second part of the question.

Sirus

Have you lot idea about the kickoff ii questions? Bear witness united states of america a little of what you accept reasoned through and your process for #iii.

ballahboy

Um.. i wasnt sure about how to do #1 and 2 so i asked. And for #iii i constitute the velocity by using 2pi*r/t and got 7.95m/s. Then i used centripetal acc.=5^2/r and got 29.4m/s^2. Wasnt certain what the 2nd question is asking.

Sirus

1. When something is moving in round motion, it is constantly changing direction. Since velocity is a vector quantity, information technology has both magnitude and management. What tin yous, therefore, conclude about objects in circular motion?

Now also consider that [tex]\vec{F}_{net}=m\vec{a}[/tex]

2. This comes from [tex]\vec{a}_{centripetal}=\frac{\vec{v}^{2}}{r}[/tex]. Basically what happens is accleration doesn't change considering when you change the radius the velocity changes likewise, making velocity squared divided past radius a consant (dispatch).

Yous besides know that [tex]\vec{F}_{centripetal}=\frac{yard\vec{v}^{ii}}{r}[/tex], and [tex]\vec{F}_{net}=one thousand\vec{a}[/tex]. Can y'all explicate what is happening?

three. Didn't check your answer just your method looks right. For the 2nd office, m=ix.81 k/s^ii, so how many "k"southward exercise the people experience?